Displaying the length of a user-entered function

So my code is:

#include<stdio.h>
#include<string.h>
int main()
{
    char name[25];
    int length;
    length = strlen(name);
    printf("Enter your name.\n");
    gets(name);
    printf("The length of your name is %d", length);
    return 0;
}

But the output only returns “1” no matter how many characters I put, wha have I done incorrectly?

• I meant displaying the length of a user entered STRING***
  - Ben

Answers

•   
  

  #include<stdio.h>
  #include<string.h>
  int main()
  {
      char name[25];
      int length;
      //You have not given any value to the variable name
      //So, the value here is 0
      //length = strlen(name);
      printf("Enter your name.\n");
      gets(name);
      //Now your variable has a value
      //So, you can calculate the length of it.
      length = strlen(name);
      printf("The length of your name is %d", length);
      return 0;
  }
  

   

  
  
• I’m confused, how does your answer differ from mine, aside from where you define the value of length, isn’t it the same code? And since I define length before I print it, why does it matter?
  - Ben
• Ohhhhh I get it now, because name doesn’t have a value before I define length, because I define length before I get the value of name, the value of length remains zero, is that correct?
  - Ben
• Yes.
  - Amit Kumar

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