C++ program to find sum of squares of numbers entered by the user till user
enters a negative number. The program will not find sum of square of a number, if it is divisible
by 3. (using do-while loop)
#include <iostream>
using namespace std;
int main() {
double a;
do{
cout<<"Number: ";
cin>>a;
if((int)a%3==0 || a<0){
cout<<endl;
}
else{
cout<<"sum of square of number: "<<a*a<<endl;
}
}while(a>=0);
return 0;
}