Write a structure to store the roll no., name, age (between 11 to 14) and address of students (more than 10). Store the information of the students. #include <iostream> using namespace std; struct student even(struct student a[]) //function for printing student names having even roll number.
1 - Write a function to print the names of all the students having age 14.
2 - Write another function to print the names of all the students having even roll no.
3 - Write another function to display the details of the student whose roll no is given (i.e. roll no. entered by the user).
struct student // defining a structure named student.
{
string name;
int roll_no;
int age;
};
// Doubt in function variable (struct student a[]).
{ int i;
for( i=0;i<5;i++){if(a[i].roll_no%2==0)
{
cout<< a[i].name<<endl;
}
}
return a[i]; // I think my return value is incorrect.
}
struct student age14(struct student a[ ]) //function for printing student names having age 14.
{ int i;
for( i=0;i<5;i++){if(a[i].age==14)
{
cout<< a[i].name<<endl;
}
}
return a[i];
}
struct student detail(struct student a[ ]) // Function for getting the detail of a particular student.
{
int i;
if(cin>>i)
{
cout<< a[i].name<<endl;
cout<< a[i].roll_no<<endl;
}
return a[i];
}
int main(int argc, char *argv[])
{ struct student a[5];
for(int i=0;i<10;i++) // loop for taking the input .
{
cout<<"Enter the name of the student"<<i+1<<endl;
cin>>a[i].name;
cout<<"Enter the roll number"<<endl;
cin>>a[i].roll_no;
}
cout<<"The students having even roll numbers are"<<endl;
// How to call the functions according to my code.
system("pause");
return 0;
}
#include <iostream>
using namespace std;
struct student // defining a structure named student.
{
string name;
int roll_no;
int age;
};
void even(struct student a[]) //function for printing student names having even roll number.
// Doubt in function variable (struct student a[]).
{ int i;
/*
You need to print the names. So, returning a[i] will
only return a student structure and not all the students.
So, the best way is to print the name inside the function itself
and use a return type of void
*/
for( i=0;i<5;i++){if(a[i].roll_no%2==0)
{
cout<< a[i].name<<endl;
}
}
// I think my return value is incorrect.
}
void age14(struct student a[ ]) //function for printing student names having age 14.
{ int i;
/*
Same logic here also
*/
for( i=0;i<5;i++){if(a[i].age==14)
{
cout<< a[i].name<<endl;
}
}
}
/*
According to the question, roll number should be passed
*/
void detail(int roll, struct student a[]) // Function for getting the detail of a particular student.
{
for(int i=0;i<5;i++)
{
if(a[i].roll_no==roll)
{
cout<< a[i].name<<endl;
cout<< a[i].roll_no<<endl;
break;
}
}
}
int main(int argc, char *argv[])
{
struct student a[5];
/*your all functions are written for array of length 5*/
for(int i=0;i<5;i++) // loop for taking the input .
{
cout<<"Enter the name of the student"<<i+1<<endl;
cin>>a[i].name;
cout<<"Enter the roll number"<<endl;
cin>>a[i].roll_no;
}
cout<<"The students having even roll numbers are"<<endl;
// How to call the functions according to my code.
even(a);
//
/*
Right now, you are not storing the age of the students.
You can call the function similary after completing it.
*/
detail(2,a);
//system("pause");
return 0;
}
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