why is it showing wrong output?

#include <stdio.h>
float result;   /* Result of the divide */
int main()

{    result = 7.0 / 22.0;
    printf("The result is %d\n", result);   

return (0); 
}

Answers

•   
  

  This is because the variable result is of type float and you are using %d to print its value. Use %f instead.

  
  
• even though it is %d it should only print integer value..but it is printing address why?
  - neha samala
• You have declared the variable result as of type float and printing it as an int. Since there is no automatic conversion of a float to an int, the compiler doesn't understand how to do the conversion. Therefore, it prints a random number (it is not address).
  - Aakhya Singh

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