Practice questions on Java Operators

class Ans{
  public static void main(String[] args){
    int x = 5
    int y = 7
    System.out.println("Area is "+(5*7)+"\nPerimeter is "+(2*(5+7)));
  }
}

class Ans{
  public static void main(String[] args){
    System.out.println((((8+2345)/3)%5)*5);
  }
}

class Ans{
  public static void main(String[] args){
    System.out.println(23 == 45);
  }
}

import java.lang.Math;
class Ans{
  public static void main(String[] args){
    System.out.println(Math.pow(7,5));
  }
}

class Ans{
  public static void main(String[] args){
    int a = 55;
    int b = 70;
    System.out.println(a < 50 && a < b);
  }
}

class Ans{
  public static void main(String[] args){
    int a = 55;
    int b = 70;
    System.out.println(a < 50 || a < b);
  }
}

class Ans{
  public static void main(String[] args){
    //using third variable
    //a = c
    //a = b
    //b = c
    //without using third variable
    //b = b-a
    //a = b+a
    //b = -(b-a)
  }
}

class Ans{
  public static void main(String[] args){
    int n, first, second, third, forth, fifth, sum;
    n = 23462;
    /*Now we will take out each digit of this number and then finally add the first and the second last digits*/
    first = n/10000;     //first digit
    n = n%10000;
	
    second = n/1000;     //second digit
    n = n%1000;
	
    third = n/100;       //third digit
    n = n%100;
	
    forth = n/10;        //forth digit
    fifth = n%10;        //fifth digit
	
    sum = first + forth;
    System.out.println("sum : "+sum);
  }
}

class Ans{
  public static void main(String[] args){
    int n, first, second, third, reverse;
    /*finding the digits of the entered number n*/
    n = 123;
    first = n/100;     //first digit
    n = n%100;
	
    second = n/10;     //second digit
    third = n%10;      //third digit
	
    /*reverse number */
    reverse = third*100 + second*10 + first;
    System.out.println("reverse number : "+reverse);
  }
}