sequence in execution of data type?

i tried a program in which i have to print a int,float and a char vaiable using input from user. In this code when i used sequence like int then float and then char it is just taking input for int and float for char it is not taking just giving output.

but if i use sequence like char > int > float then it is working properly . why?

Answers

•    XylasheSD
  

  The sequence in which you read input from the user can impact your program's behavior due to how input buffering operates in many programming languages when reading from the standard input stream. When you input data, the program reads characters until it encounters a newline or whitespace character, interpreting the input according to the expected data type.

  For example, when using the sequence "int > float > char," it works as expected because each input is followed by a newline character. The program correctly interprets the integer, float, and character inputs without interference.

  However, with the sequence "char > int > float," issues can arise. After entering a character, the newline character remains in the input buffer. When the program attempts to read an integer, it encounters this lingering newline, causing unexpected behavior or potentially skipping input entirely.

  To mitigate this, it's essential to manage the input buffer correctly. You can clear it using functions like fflush(stdin) in C/C++ or handle input as entire lines, parsing them into the desired data types afterward. This approach ensures that the program processes input in a predictable manner and avoids complications arising from leftover newline characters.
  

  
  

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