The program suppose to get much integers as a user want and then convert each integer into word but the pointer seem not working correct

#include <stdio.h>
int main()
{
    int  array[100],n,i,digit;
    int *ptr;

    printf("Enter the size of the array:\t");
    scanf("%d",&n);

    
    for(i=0; i<n; i++)
    {
    printf("Enter element %d:\n",i+1);
    scanf("%d", &array[i]);

    ptr=array[i];
    digit=ptr;

switch (digit)
     {
    case 0:
         printf("zero");
         break;
    case 1:
         printf("one");
         break;
    case 2:
         printf("two\n");
         break;
    case 3:
         printf("three");
         break;
    case 4:
        printf("four");
        break;
    case 5:
        printf("five");
        break;
    case 6:
        printf("six");
        break;
    case 7:
        printf("seven");
        break;
    case 8:
        printf("eight");
        break;
    case 9:
        printf("nine");
        break;
    default:
        printf("\nYou must enter a valid number");
        break;
     }
     ptr++;

     //To print the number you enter in word
     for(i=0; i<n; i++)
     {
          printf("%d\t",ptr);

     }

    }
}

• Please explain the code little. It is not clear what are you trying to do.
  - Amit Kumar

Answers

•   
  

  hello, your code was correct but you added unwanted code.just deleted unwanted code.now the code runs fine.

  #include <stdio.h>
  int main()
  {
      int  array[100],n,i,digit;
      int *ptr;
  
      printf("Enter the size of the array: ");
      scanf("%d",&n);
    for(i=0; i<n; i++)
      {
      printf("Enter element %d: ",i+1);
      scanf("%d", &array[i]);
  
      ptr=array[i];
      digit=ptr;
  
  switch (digit)
       {
      case 0:
           printf("zero\n");
           break;
      case 1:
           printf("one\n");
           break;
      case 2:
           printf("two\n");
           break;
      case 3:
           printf("three\n");
           break;
      case 4:
          printf("four\n");
          break;
      case 5:
          printf("five\n");
          break;
      case 6:
          printf("six\n");
          break;
      case 7:
          printf("seven\n");
          break;
      case 8:
          printf("eight\n");
          break;
      case 9:
          printf("nine\n");
          break;
      default:
          printf("\nYou must enter a valid number");
          break;
       }
   }
  }
  

   

  
  

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